- ∫5sinb db
- ∫5cosm dm
- ∫5sinb + 9b^4 db
- ∫5/x dx
- Find the derivative of the following
Let f(t) = 5 cos t , f(x) = sin x, Let f(x) = 3cos x + 5x, Let f(t) = 2t + sin t. f(t) = 1/t2 - sin t, Let f(x) = sin x - cos x. Let f(x) = 2sin x + 3cos x. Let f(x) = 4sin x + 1/x.
Let f(t) = -3sin t + 1/2 cos t.
6. Find the integration of the following
Let f(t) = 5 cos t , f(x) = sin x, Let f(x) = 3cos x + 5x, Let f(t) = 2t + sin t. f(t) = 1/t2 - sin t, Let f(x) = sin x - cos x. Let f(x) = 2sin x + 3cos x. Let f(x) = 4sin x + 1/x. Let f(t) = -3sin t + 1/2 cos t.
for no 1;
ReplyDeleteintegrating 5 sinb db gives
-5cos b db
for no 2
ReplyDeleteintegrating 5 cos mdm gives
5sinm dm
for no 3
ReplyDeleteans= -5cosb + 9b^5/5
i real trying so if ah wrong tell me k
ReplyDeletefor f(t)= 5cos t
ReplyDeletedf/dt= -5sin t
f(x)= sin x
ReplyDeletedf/dx= cos x
for f(x)= 3cos x + 5x
ReplyDeletedf/dx = -3 sin x + 5
for f(x)= 2t + sin t
ReplyDeletedf/dt= 2 +cos t
for f(x)= 1/t2 - sin t
ReplyDelete= 1t^-2 - sin t
df/dt= -2t^-3 - cos t
ZOE
ReplyDeleteWhen integrating why are you putting db
for no 1;
integrating 5 sinb db gives
-5cos b + C
No 3 Integrate wrt x
Let f(x) = 3cos x + 5x
3sinx + 5/2 x^2 + C
What exactly did you do
for no 3
ans= -5cosb + 9b^5/5
for f(x)= sin x - cos x
ReplyDeletedf/dx= cos x - -sin x
cos x = sin x
for f(x)= 2sin x + 3cos x
ReplyDeletedf/dx= 2cos x - 3 sin x
f(x)= 4sin x + 1/x
ReplyDelete4sin x + 1x^-1
df/dx= 4cos x + -1x^-2
miss for no. 3 i added 1 to the power and divided by the new power.. ent that is the rule?
ReplyDeletemiss i scared abt exam.... think we cud do some practice sessions tomorrow??
ReplyDeletemiss for no. 3 i added 1 to the power and divided by the new power.. ent that is the rule?
ReplyDeleteLet f(x) = 3cos x + 5x
How many terms are in this question?
2
What are they?
3cosx
5x
Now integrate each
3cosx integrated will give 3sinx
5x integrated will give
what is the power of x? 1
add 1 to the power and divided by the new power.. ent that is the rule?
2 is the new power
so 5x/2
miss this thing giving ducklin a headache honestly
ReplyDeletemiss please do one as a example so i could see how to do it
ReplyDelete(1) 5sinb db
ReplyDelete-5cosb+c
(2)5cosm dm
5sinm +c
check and see if that right
(3)5sinb+9b^4 db
ReplyDelete-5cosb+9b^5/5+c
(4)5/x dx
5/x +c
This comment has been removed by the author.
ReplyDelete#2
ReplyDelete∫5cosm dm
intergrate
5sinm dm
#3
ReplyDelete∫5sinb + 9b^4 db
-5cosb + 9b^5/5
(5) i just did two
ReplyDelete(fx)=4sinx+1/x
df/dx=4cosx+x^-1
4cosx-x^-2
f(t)= -3sint+1/2cost
df/dt=-3cos-1/2sint
grape how you going girl i see you bloging
ReplyDelete∫5sinb db
ReplyDeletethe answer is -5 cosb + c
5cosm dm
ReplyDeletethe answer is 5 sin m + c
if i wrong can someone help me because i am really confused
ReplyDelete(6) f(t)=5cost
ReplyDelete5cost f(t)
5sint+c
f(x)=sinx
sinx f(x)
-cosx+c
_
number (1)
ReplyDeleteintegrating 5 sinb db equals
-5cos b db
number (3)
ReplyDelete∫5sinb + 9b^4 db
-5cosb + 9b^5/5
i dont even know where to begin answering these questions!!!!!!!
ReplyDeletehi sunflower its nice to know i'm not alone
ReplyDeletemiss for #1, how come db gives you +c
ReplyDeletecan someone show me how to do #4
ReplyDeletecan someone show me how to do this
ReplyDeletef(x)=4sinx + 1/x
is the opposit of sinx -cosx or cosx
ReplyDeletesnowwhite i trin something an i may be wrong so
ReplyDeletef{x}=4sinx+(1/x) (1/x)=1^-x
dy/dx=-4cosx-x^-1
Let f(x) = 3cos x + 5x
ReplyDeletedy/dx=-3sinx+5x/2
1)∫5sinb db
ReplyDelete= -5cosb + c
2)∫5cosm dm
ReplyDelete= 5sinm + c
3)∫5sinb + 9b^4 db
ReplyDelete= -5cosb + [9b(4+1)]/5 + c
= -5cosb + 9b^5/5 + c
4)∫5/x dx
ReplyDelete∫5x^-1 dx
=[5x(-1+1)]/0 + c
=5lnx + c
tanx for that explaination miss.. i think i get it now..
ReplyDeletein that explanation,how come u got 2 and why 3sinx was not included?
ReplyDeleteok are we going to get questions like this for exams
ReplyDeleteThis comment has been removed by the author.
ReplyDeletenumber3:
ReplyDelete∫5sinb + 9b^4 db
= -5cosb + 9b(4+1)/5 + c
= -5cosb + 9b^5/5 + c
number4:
ReplyDelete∫5/x dx
∫5x^-1 dx
=[5x(-1+1)]/0 + c
can someone complete my questionplease and explain why and how you did it... :)
∫5/x dx
ReplyDelete=∫(1/x)5 dx
the integral of 1/x = ln x + c
therefore
∫(1/x)5 dx
=5 ln x + c
posting up some questions to try.
ReplyDelete(1)∫ sinx + 2.
(2)∫ cosx - sinx
(3)∫ 5cosx + 4 sinx - 1 between the limits 3 and 1
ReplyDelete(4)∫ 3 - x^1/2 + 1/2sinx
no6. Let f(x) = sin x - cos x.
ReplyDelete∫ sin x - cos x.
= -cosx - sinx + c
no6. f(t) = -3sin t + 1/2 cos t
ReplyDelete∫ -3sin t + 1/2 cos t
= 3cos t + 1/2 sin t
no5 let f(x) = 2sin x + 3cos x
ReplyDeletedy/dx = 2cosx - 3sinx
1). y= 5sinb db
ReplyDeletethe integral of that is -5cosb + c
2). y=5cosm dm
ReplyDeletethe integral of that is 5sinm + c
3). y=5sinb+9b^4
ReplyDeletethe integral of that is -5cosb+36/5b^5
4). y=5x^-1
ReplyDeletethe integral of that is -5x^0/0
= 0
This comment has been removed by the author.
ReplyDelete7). f(x)= sin x
ReplyDeletedf/dx= cos x
7). f(x)= 3 cos x + 5x
ReplyDeletedf/dx= -3sin x + 5
7). f(x)= 4sin x + 1x^-1
ReplyDeletedf/dx= 4cos x - 1x^-1
7). f(t)= -3sin t + 1/2 cos t
ReplyDeletedf/dx= -3cos t - 1/2sin t
5). f(t)= 5 cos t
ReplyDeletedf/dt= -5 sin t
it supposed to no 5 not no 7 for the question above.
ReplyDelete6). f(t)= 5 cos t
ReplyDeletethe integral of that is 5 sin t
6). f(x)= sin x
ReplyDeletethe integral of that is - cos x
6). f(x)= 3 cos x + 5x
ReplyDeletethe integral of that is 3 sin x + 5/2x^2
6). f(t)= 2t + sin t
ReplyDeletethe integral of that is t^2 - cos t
6). f9t)= 1t^-2 - sin t
ReplyDeletethe integral of that is -t^-1 + cos t
6). f(x)= sin x - cos x
ReplyDeletethe integral of that is - cosx - sinx
6). f(x)= 2sinx + 3cosx
ReplyDeletethe integral of that is -2cosx + 3sinx
6). f(t)= -3sint + 1/2cost
ReplyDeletethe integral of that is 3cost + 1/2sint
3)5sinb+9b^4 db
ReplyDelete-5cosb+9b^5/5+c
(4)5/x dx
5/x +c
6). f(x)= 2sinx + 3cosx
ReplyDeletethe integral of that is -2cosx + 3sinx
question 1
ReplyDeletethe integral of 5sinb db
=-5cosb + c
question 2
ReplyDeletethe integral of 5cosm dm
=5sinm + k
question 3
ReplyDeletethe intergal of 5sinb + 9b^4 db
=-5cosb + 9/5b^5 db
question 4
ReplyDeletethe integral of 5/x dx
=5ln[x] + k
INTEGRATING IS REALLY CONFUSING. I KNOW ITS KINDA LATE IN SAYING DAT NOW!!!!!!!!
ReplyDeleteOMG i need help...lol
ReplyDeletewhy in the integral of 5sinb db the 5 turns to negative???? i doh undastan...
ReplyDeleteQ4.
ReplyDeleteintegral of 5/x dx:
= 5x^-1
integral = 5 + c
Don't ask how i arrived at this..cuz i doh kno mihself.... if any1 can clarify this, please do..
Let f(t) = 5 cos t ,
ReplyDeletedf/dt=-5sin t
f(x) = sin x,
dy/dx=cos x
Let f(x) = 3cos x + 5x,
dy/dx=-3sin x +5
Let f(t) = 2t + sin t.
dt/dx=2 + cos t
f(t) = 1/t2 - sin t,
f(t)= 1 (t)^-2 - sin t
dt/dx=-2t^-3 - cos t
dt/dx=-2/t^3 - cos t
Let f(x) = sin x - cos x.
dy/dx= cos x +sin x
Let f(x) = 2sin x + 3cos x.
dy/dx=2cos x - 3sin x
Let f(x) = 4sin x + 1/x
f(x)=4sin x + 1(x)^-1
dy/dx=4cos x -1x^-2
dy/dx=4cos x -1/x^2
Let f(t) = -3sin t + 1/2 cos t.
f(t)=-3sin t + 1 (2 cos t)^-1
dt/dx= -3cos t - 1 (-2sin t)^-2
dt/dx=-3cos t -1/-2sin t^1
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